Primary exercises
- Manually created factor.
In a study participants were asked whether their sport activity is none, oncePerWeek, severalPerWeek or daily.
Build a proper factor for the responses below and store it in a variable w.
Print the factor.
Write the code to count the numbers of occurrences of each level and print the counts.
severalPerWeek, none, none, oncePerWeek, oncePerWeek, oncePerWeek, oncePerWeek, ?, none, none
v <- c( "severalPerWeek", "none", "none", "oncePerWeek", "oncePerWeek", "oncePerWeek", "oncePerWeek", NA, "none", "none" )
w <- factor( v, levels = c( "none", "oncePerWeek", "severalPerWeek", "daily" ) )
w
[1] severalPerWeek none none oncePerWeek oncePerWeek oncePerWeek oncePerWeek <NA> none
[10] none
Levels: none oncePerWeek severalPerWeek daily
fct_count( w )
# A tibble: 5 × 2
f n
<fct> <int>
1 none 4
2 oncePerWeek 4
3 severalPerWeek 1
4 daily 0
5 <NA> 1
- A factor with a random content.
Read help about the function sample.
Then study and try the following lines of code to understand the results.
Next, understand why an error is generated and use replace argument to generate a vector with 100 samples.
Store this vector in a variable v and build a factor w from it.
Finally, count the numbers of occurrences of each level in w.
Ensure, that levels are in order provided in the variable lvs.
lvs <- c( "none", "oncePerWeek", "severalPerWeek", "daily" )
sample( lvs, 3 )
[1] "severalPerWeek" "none" "daily"
sample( lvs, 3 )
[1] "severalPerWeek" "daily" "none"
sample( lvs, 3 )
[1] "oncePerWeek" "severalPerWeek" "none"
sample( lvs, 100 )
Error in sample.int(length(x), size, replace, prob): cannot take a sample larger than the population when 'replace = FALSE'
v <- sample( lvs, 100, replace = TRUE )
w <- factor( v, levels = lvs )
w
[1] severalPerWeek none oncePerWeek daily daily severalPerWeek severalPerWeek daily daily
[10] severalPerWeek none none severalPerWeek severalPerWeek none oncePerWeek severalPerWeek none
[19] severalPerWeek daily daily oncePerWeek severalPerWeek daily none daily daily
[28] severalPerWeek daily severalPerWeek oncePerWeek none oncePerWeek oncePerWeek none severalPerWeek
[37] oncePerWeek oncePerWeek oncePerWeek daily severalPerWeek daily oncePerWeek none oncePerWeek
[46] none none severalPerWeek severalPerWeek daily none severalPerWeek oncePerWeek oncePerWeek
[55] severalPerWeek none none none oncePerWeek severalPerWeek none daily oncePerWeek
[64] severalPerWeek none severalPerWeek none severalPerWeek oncePerWeek oncePerWeek none none
[73] severalPerWeek daily oncePerWeek severalPerWeek daily severalPerWeek daily severalPerWeek none
[82] none daily severalPerWeek oncePerWeek severalPerWeek none severalPerWeek severalPerWeek oncePerWeek
[91] oncePerWeek severalPerWeek severalPerWeek severalPerWeek daily none oncePerWeek severalPerWeek daily
[100] oncePerWeek
Levels: none oncePerWeek severalPerWeek daily
fct_count( w )
# A tibble: 4 × 2
f n
<fct> <int>
1 none 24
2 oncePerWeek 23
3 severalPerWeek 33
4 daily 20
- Reordering factor levels.
When a factor is shown on an axis of a plot, the order is given by its levels.
The factor w from the previous exercise will be then shown in this order: none, oncePerWeek, severalPerWeek, daily.
But for a picture in a manuscript the following order might be needed: daily, severalPerWeek, oncePerWeek, none.
Apply to w one of the fct_ functions from the tidyverse library to produce a factor w2 with the requested order.
Show the levels of w2.
Again show the number of elements of each level in w2 and compare it with the table of the previous exercise.
w2 <- fct_relevel( w, c( "daily", "severalPerWeek", "oncePerWeek", "none" ) )
levels( w2 )
[1] "daily" "severalPerWeek" "oncePerWeek" "none"
fct_count( w2 )
# A tibble: 4 × 2
f n
<fct> <int>
1 daily 20
2 severalPerWeek 33
3 oncePerWeek 23
4 none 24